Quick answer :
Area of this shape = 614²
Answer with steps :
Length of side of the first square = 10
It's area :
![=\tt side * side](https://img.qammunity.org/2022/formulas/mathematics/high-school/vt1h4xdv49qbuokcxq9u9apofiwzrh50ds.png)
![= \tt10 * 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/9f8m6kep9wsn6coyfou4n2ccjh9gel0yso.png)
![= \tt {100}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9vokjcdo17lebe3vg7aaj5wnzci3x3otmm.png)
Thus, the area of the first square = 100²
Length of the side of the second square = 10
It's area :
![= \tt \: side* side](https://img.qammunity.org/2022/formulas/mathematics/high-school/yootwfmtwnp2hqr6m9finn83aj5vvbwhi7.png)
![=\tt 10 * 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/vaw8fb681tocn7688lqzqpkx1z3fpsb23b.png)
![= \tt{100}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mftkecvlin68v82zbg2j5a53o9xlvq4ypu.png)
Thus, the area of the second square = 100²
Length of the side of the third square = 10
It's area :
![=\tt side * side](https://img.qammunity.org/2022/formulas/mathematics/high-school/vt1h4xdv49qbuokcxq9u9apofiwzrh50ds.png)
![= \tt 10 * 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/aqli14nhkxv34r6zji99rhm02fegfsah7v.png)
![= \tt {100}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9vokjcdo17lebe3vg7aaj5wnzci3x3otmm.png)
Thus, the area of the third square = 100²
(pi value = 3.14)
Radius of the first semicircle = 10 cm
It's area :
![= \tt \: \frac{\pi {r}^(2) }{2}](https://img.qammunity.org/2022/formulas/mathematics/high-school/s46h6ktdsq9tj1nc1adrgsa6ziyphrrimn.png)
![= \tt (3.14 * 10 * 10)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o2766f2r76miuo8yz1t850jcfr8weeyutx.png)
![= \tt(3.14 * 100)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/bk3njq9obvsnjaxoxkhphocuwiq71ek17v.png)
![=\tt (314)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ws0te6lmqku52pwcfq6i8krhiequ2tymz1.png)
![=\tt {157}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/lfagefdmo79seqxzb99n1qsitljmayfz4c.png)
Thus, the area of the first semicircle = 157²
Area of the second semi circle :
= area of the first semicircle
= 157²
Thus, the area of the second semicircle = 157²
Total area of the figure :
= Area of the 3 squares + Area of the two semi circles
![=\tt 100 + 100 + 100 + 157 + 157](https://img.qammunity.org/2022/formulas/mathematics/high-school/5qo3r2d2n9ldulwi74vb6xpthebmasmnua.png)
![= \tt300 + 314](https://img.qammunity.org/2022/formulas/mathematics/high-school/fbcy33j57jw55ek3kcg2nlerqxgy9tyoo3.png)
![= \tt {614}^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/yhkg89b5qki8gxe116nr15sruhdlmlgbvn.png)
Therefore, the total area of the figure = 614²