Answer:
The operation is commutative
Explanation:
Operations
The * operation is defined on the set of real numbers R by
![a * b=a^3+b^3-3ab](https://img.qammunity.org/2022/formulas/mathematics/high-school/xap5paisuow0045wmadbafs74ams43y5a4.png)
For the operation to be commutative a*b should be equal to b*a.
Computing b*a:
![b * a=b^3+a^3-3ba](https://img.qammunity.org/2022/formulas/mathematics/high-school/jaic9gx4bq0yssas2z9rp8maus4cek5xm7.png)
Rearranging:
![b * a=a^3+b^3-3ab](https://img.qammunity.org/2022/formulas/mathematics/high-school/pj3rjeapteaj95iqlgkhztbaie3f3prswu.png)
It's apparent that a*b=b*a, thus the operation is commutative