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Use the rules for logarithms and exponents to solve for pH in terms of [H+]pH=

Use the rules for logarithms and exponents to solve for pH in terms of [H+]pH=-example-1
User Daniel Beer
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1 Answer

24 votes
24 votes

Answer:

pH = -log[H+]

Step-by-step explanation:

From the equation of [H+], we can find the equation for pH, clearing pH by passing 10 to the other side of the equation as logarithm to base 10, and then the negative sign:


\begin{gathered} \lbrack H^+\rbrack=10^(-pH) \\ log\lbrack H^+\rbrack=-pH \\ -log\lbrack H^+\rbrack=pH \end{gathered}

User Sudik Maharana
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