Question

How much more current can safely be drawn from a 120 V outlet fused at 15 A if a 600 W curling iron and a 1200 W hair dryer are operating in the circuit.

Answer 1

First we must calculate the current power the curling iron can handle:

`P=I* V`

where

I = current

V = tension

Then:

`\begin{gathered} 600=I*120 \\ I=5A \end{gathered}`

For the hair dryer we get:

`\begin{gathered} P=I* V \\ 1200=I*120 \\ I=10A \end{gathered}`

Lets suppose all appliances are working in parallel together. The total current must be:

`\begin{gathered} I=I_1+I_2 \\ I=5+10 \\ I=15A \end{gathered}`

As we can see the appliances are drawning all current from the outlet fused.

Answer: the current that can be safely drawn from the outlet fused is zero.