209k views
0 votes
Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius.


help me please ...?

User Chrisbyte
by
8.2k points

1 Answer

5 votes
Radii and chord form an equilateral triangle. The angle of the larger segment is
360^o-60^o=300^o.

The length of the larger segment is


l= (2r\pi\alpha)/(360^o)= (2* 8\pi300^o)/(360^o)= ( 16\pi5)/(6)= ( 8\pi5)/(3)=( 40\pi)/(3)
User Houssein Zouari
by
7.8k points