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In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of allele a is 0.1. what is the percentage of the population that is heterozygous for this allele?
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In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of allele a is 0.1. what is the percentage of the population that is heterozygous for this allele?

User Jan Stanicek
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10% because p+q=1 in equilibrium and if p is .1 then q is .9 so p is 10% and q is 90%
User Lionel Henry
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