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D/dt integral from 0,2x of (e^t+2t)dt is?

User Wlads
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1 Answer

3 votes
they appear to be using the (2x) as the variable;
so,
e^(t) + t^2 ;
now fill in the interval [0,2x]
e^(2x) + (2x)^2 -e^(0)
D{t} [e(2x) +4x^2 - 1]
2e^(2x) + 8x

User Rubioli
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