Question

For all x > 0 and y > 0, the radical expression:

√x divided by 3√x-√y is equivalent to.
3x + √xy divided by 9x-y.
SOLVE.

Answer 1

`( √(x) )/(3 √(x) - √(y) ) = (3x+ √(xy) )/(9x-y) =(3x+ √(xy) )/((3 √(x) - √(y))(3 √(x) + √(y))) \\ √(x) =( √(x) (3 √(x) + √(y)) )/((3 √(x) + √(y))) \\ √(x) = √(x) \\ 1=1`