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On a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 19 min, and a 1100-W microwave oven, 3.5 min. With these power requirements, find how much it costs to use these appliances at an electrical cost of 7¢ per kWh. (Do not round your final answer. Fractional cent values are acceptable.) answer with:___¢

User Thegreenpizza
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2 Answers

17 votes
17 votes

Final answer:

To find the cost of using a 1600-W coffee maker for 19 minutes and a 1100-W microwave for 3.5 minutes at a cost of 7¢ per kWh, we calculate the energy consumed by each appliance and then multiply the total kWh by the cost per kWh, resulting in approximately 4¢ total cost.

Step-by-step explanation:

To calculate the cost of using a 1600-W coffee maker for 19 minutes and a 1100-W microwave oven for 3.5 minutes at an electrical cost of 7¢ per kWh, we need to convert the power and time into kilowatt-hours (kWh). The formula for energy consumption in kWh is Power (in kW) × Time (in hours).

First, we convert the power of the appliances to kilowatts (kW):

  • Coffee maker: 1600 W = 1.6 kW
  • Microwave oven: 1100 W = 1.1 kW

Next, calculate the time in hours:

  • Coffee maker: 19 min = 19/60 hour = 0.3167 hour
  • Microwave oven: 3.5 min = 3.5/60 hour = 0.0583 hour

Then we calculate the energy consumption:

  • Coffee maker energy: 1.6 kW × 0.3167 hour = 0.5067 kWh
  • Microwave oven energy: 1.1 kW × 0.0583 hour = 0.0641 kWh

Now, combine the total energy consumption and calculate the cost:

Total energy = 0.5067 kWh (Coffee maker) + 0.0641 kWh (Microwave oven) = 0.5708 kWh

Total cost = 0.5708 kWh × 7¢/kWh

Total cost = 3.9956¢

Therefore, the total cost for using both appliances is approximately 4¢.

User Jeyaram
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3.4k points
25 votes
25 votes

The first step is to convert the times from minutes to hours.

Recall,

60 min = 1 hour

19 min = 19/60

3.5 min = 3.5/60

Considering the 1600-W coffee maker,

Consumption = 1600 x 19/60 = 506.67 kwh

Considering the 1100-W microwave oven,

Consumption = 1100 x 3.5/60 = 64.17 kwh

Total consumption = 506.67 + 64.17 = 570.84 kwh

Given that the cost is 7¢ per kWh,

cost of using these appliances = 570.84 x 7

cost of using these appliances = 3995.88¢

User PrivateOmega
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3.1k points