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What is the equation of the lineA. Y=-4/3xB. Y=-3/4xC. Y=3/4xD. Y=4/3x

What is the equation of the lineA. Y=-4/3xB. Y=-3/4xC. Y=3/4xD. Y=4/3x-example-1
User Grayasm
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1 Answer

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In order to determine the equation of the given line, take into that the general form of the equation of a line is:

y = mx + b

where m is the slope of the line and b the y-intercept.

To find m use the following formula:

m = (y2 - y1)/(x2 - x1)

where (x1,y1) and (x2,y2) are two points on the line.

Use (x1,y1) = (-4,-3), (x2,y2) = (4,3):

m = (3 - (-3))/(4 - (-4)) = 6/8 = 3/4

The y-intercept is the value of y when x=0.

You can notice that such value is b=0.

Hence, the equation of the given line is:

y = 3/4x