Question

. If the electrical force of repulsion between two same amount of charges is 10 N, andthey are 30000 m apart. What is the magnitude of each charge?

Answer 1

Step-by-step explanation:

Given: q₁ = q₂,

F= 10 N,

distance between two charges, r = 30000 m.

We have,
`F = (q_(1) q_(2) )/(4\pi Er^(2) )`

Hence,
`q_(1) q_(2) =F * 4\pi *E *r^(2)`

E (epsilon) =
`8.85 * 10^(-12) C^(2) /Nm`

Substituting the values, we have,

`q_(1) q_(2) = 1 C`

Hence
`q_(1) = q_(2) = 0.5 C`