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3x^2-2xy+3x-2y factor by grouping

User Fjarlq
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you'll want to group them where they'll factor out easier; 3x^2 and 3x match well, and -2xy and -2y match well.

(3x^2 + 3x)(-2xy - 2y)

then you factor out a piece from each:

3x can come out of the first pair
-2y can come out of the second

3x(x + 1) - 2y(x + 1)

the goal of facoring by grouping is to factor in a way that gets you the same binomial within your parentheses, because once those are the same, you can factor the ENTIRE binomial out to leave you with your other factor:

(x + 1)(3x - 2y)

those are your two factors
User Bennidhamma
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