Question

Question 4 (1 point)How many solutions does 9x? + 6x + 1 = 0 have?

Answer 1

We have the next equation

`9x^2+6x+1=0`

we will use the second- degree general formula

`x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In our case

a=9

b=6

c=1

we substitute

`x_(1,2)=\frac{-6\pm\sqrt[]{6^2-4(9)(1)}}{2(9)}`

we simplify

`x_(1,2)=\frac{-6\pm\sqrt[]{36-36}}{2(9)}=-(1)/(3)`

As we can see we have one real solution with a multiplicity of 2

ANSWER

one real solution with multiplicity 2