Answer:
Up
Explanation:
Let the parent function be y=|x|
Rule : f(x)→f(x-b)
So, the graph shifts right by b units
So, shift the parent graph by 4 units to right
So, using rule |x|→|x-4|
So, new function = |x-4|
Rule :f(x)→f(x)+b
So, the graph shifts up by b units
So, shift the obtained graph by 3 units up
So, |x-4|→|x-4|+3
Thus the direction of the graph of y=|x-4|+3 open is up
Hence Option D is correct.