Question

A large stone cube has side length 4 meters and mass 640000 kg. What is the pressure on the ground face of the cube?

Answer 1

Given:

The side length of the cube, a4 m

The mass of the cube, m=640000 kg

To find:

The pressure on the ground face of the cube.

Step-by-step explanation:

The area of the ground face of the cube is,

`\begin{gathered} A=a^2 \\ =4^2 \\ =16\text{ m}^2 \end{gathered}`

The force applied on the ground face of the cube is equal to the weight of the cube.

The pressure on th ground cface of the cube is given by,

`\begin{gathered} P=(F)/(A) \\ =(mg)/(A) \end{gathered}`

Where F is the force applied on the ground face of the cube and g is the acceleratin due to gravity.

On substituting the known values in the above equation,

`\begin{gathered} P=(640000*10)/(16) \\ =4*10^5\text{ Pa} \\ =4\text{E}5\text{ Pa} \end{gathered}`

Final answer:

Thus the correct answer is option f.