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38 votes
38 votes
3a raised to 7, b raised 6 / 18a raised to 6 , b raised to 8

3a raised to 7, b raised 6 / 18a raised to 6 , b raised to 8-example-1
User EnglishPete
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1 Answer

9 votes
9 votes

Solution:


(3a^7b^6)/(18a^6b^8)
\begin{gathered} (3a^(7)b^(6))/(18a^(6)b^(8))\text{ = }(3)/(18)\text{ .}(a^7)/(a^6).(b^6)/(b^8) \\ Appying\text{ the law of indices, } \\ \text{ }(3)/(18)\text{ .}(a^7)/(a^6).(b^6)/(b^8)\text{ = }(1)/(6)a^(7-6)b^(6-8) \\ \\ =(a^1b^(-2))/(6) \\ =(a)/(6b^2) \\ \\ The\text{ answer is }(a)/(6b^2) \end{gathered}

User EXODIA
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