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20 votes
20 votes
Last softball season, Pamela had 46 hits, a combination of singles (1 base), doubles (2 bases), and triples (3 bases). These hits totaled 67 bases, and she had 4 times as many singles as doubles. How many doubles did she have?

User ETO
by
2.7k points

1 Answer

14 votes
14 votes

Let's define the next variables:

x: amount of singles

y: amount of doubles

z: amount of triples

Pamela had 46 hits, then:

x + y + z = 46 (eq. 1)

These hits totaled 67 bases, then:

x + 2y + 3z = 66 (eq. 2)

she had 4 times as many singles as doubles, then:

x = 4y (eq. 3)

Substituting equation 3 into equations 1 and 2, we get:

4y + y + z = 46

5y + z = 46 (eq. 4)

4y + 2y + 3z = 67

6y + 3z = 66 (eq. 5)

Isolating z from equation 4:

5y + z = 46

z = 46 - 5y (eq. 6)

Substituting equation 6 into equation 5, we get:

6y + 3(46 - 5y) = 66

6y + 3*46 - 3*5y = 66

6y + 138 - 15y = 66

6y - 15y = 66 - 138

-9y = -72

y = (-72)/(-9)

y = 8

She had 8 doubles.

User Lucina
by
2.3k points
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