Question

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 meters. Determine the acceleration of the car

Answer 1

`\Delta x = (1)/(2) a t^(2)`

`110 = (1)/(2) (a) (5.21)^(2)`

`a = (200)/(5.21^(2))`

`a = 8.10 m/s^2`