Question

How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)

Answer 1

Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L

Answer 2

1.81 liters of KCl solution

Step-by-step explanation:

Molarity is expressed as:

`Molarity=(molesofsolute)/(litersofsolution)`

Solving for Liters of solution:

Liters of solution =
`(molesofsolute)/(Molarity)` (1)

Using the molecular weight fo the KCl to find the moles of solute:

`15.00gKCl*(1molKCl)/(74.6gKCl)=0.20molesKCl`

Replacing in the formula (1):

Liters of solution =
`(0.20molesKCl)/(0.1107M)`

Liters of solution = 1.81 liters