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How many liters of water must be added to 50L of a 30% acid solution in order to produce a 20% acid solution?

User Pepuch
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1 Answer

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Let x be the water added
.30*50 = .20(50 L +x)
simplify and Solve

.30*50 - .20*50 L = .20x
.10*50L = .20x
25L = x
25 liters of water would need to be added
checking our answer
15 = .20(75) hope this helps :)
User Jlf
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8.6k points

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