Question

Help with this question1

Answer 1

Step-by-step explanation

Given

`f(x)=x^3+6x^2+5x-12`

From the constant, the possible roots includes , -1, -2, -3, -4, -6, -12. If we test -4 in the function , we will have;

`f(x)=(-4)^3+6(-4)^2+5(-4)-12=-64+96-20-12=0`

Since f(x)=0, it implies that x=-4 is a root, which makes x+4 a factor of the equation

Answer: Option D