Question

4(u+3)-6u=32solve for u.

Answer 1

The solution to the equation is;

`u=-10`

Step-by-step explanation:

Given the equation;

`4(u+3)-6u=32`

let us expand and solve;

`\begin{gathered} 4u+12-6u=32 \\ 4u-6u+12=32 \\ -2u+12=32 \\ -2u=32-12 \\ -2u=20\text{ ------divide both sides by -2} \\ u=(20)/(-2) \\ u=-10 \end{gathered}`

Therefore, the solution to the equation is;

`u=-10`