Question

Help with question 9 I just need a fresh explanation because I don’t get the way my teacher does it

Answer 1

Answer: 0.13 moles of KCl

Explanation:

The balanced chemical reaction :

`10KClO_3+3P_4\Rightarrow3P_4O_(10)+\text{ 10KCl }`

GIVEN

• Mass of Potassium chlorate KClO3 = 16 g

,

• Molecular mass KClO3 = 122,55 g/mol

(1) Calculate moles of KClO3

`\begin{gathered} Moles\text{ = }\frac{Mass\text{ KClO}_3}{Molecular\text{ Mass KClO}_3} \\ \text{ = }\frac{16g\text{ }}{122.55\text{ g.mol}^(-1)} \\ \text{ =0.131 moles of KClO}_3 \end{gathered}`

(2) By stoichiometry, the balanced equation informs us that :

10 moles KClO3 produces 10 moles KCl

therefore ;

0.131 moles of KClO3 will produce 0.13 moles of KCl

{ take note that the ratio if 1:1 , meaning for every 1 mole of KClO3 , 1 mole of KCL willbe produced }