Question

After growing tired of squinting while driving, Donald went shopping for a pair of sunglasses. He tried glasses with different frames and lenses. Cat eye frames Browline frames Aviator frames Polarized lenses 2 5 2 2 4. 4 Regular lenses What is the probability that a randomly selected pair of sunglasses has regular lenses or cat eye fra Simplify any fractions,

Answer 1

From our table, we have

`P(\text{regular lenses)=}(2+4+4)/(19)=(10)/(19)`

similarly

`P(\text{cat eye frame)=}(2+2)/(19)=(4)/(19)`

and the searched probability is

`P(\text{regular lenses }\cup\text{ cat eye frame)=}P(\text{regular lenses)}+P(\text{ cat eye frame)-}P(\text{regular lenses }\cap\text{ cat eye frame)}`

which gives

`\begin{gathered} P(\text{regular lenses }\cup\text{ cat eye frame)=}(10)/(19)+(4)/(19)-(2)/(19) \\ P(\text{regular lenses }\cup\text{ cat eye frame)=}(12)/(19) \end{gathered}`

then, the answer is

`P(\text{regular lenses }\cup\text{ cat eye frame)=}(12)/(19)`