Question

Directions: Write the balanced equation for each of the following situations. . In addition, list the reaction type. YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS GO TO COMPLETION. If only STOICHIOMETRY, tell how much of the excess reactant is used!!!! Reaction Type a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction 4. 3.59 x 102 g strip of zinc is dropped into a test tube of containing excess hydrochloric acid 4. Balanced Chemical Equation Reaction Type:At the completion of reactions: Grams of zinc metal: Grams of hydrochloric acid: Grams of zinc chloride: Grams of hydrogen gas:

Answer 1

First, let's write and balance the reaction of zinc with hydrochloric acid:

Zn + 2 HCl --> ZnCl2 + H2

This reaction type is c. single displacement, also an oxidation-reduction reaction.

At the beginning of the reaction, we have 3.59 x 10^2 g of zinc metallic.

Let's calculate how many grams of HCl are consumed and how many grams of zinc chloride and hydrogen gas are formed.

For this, we use the following equation: mole = mass / molar mass

- Step 1. We are going to transform zinc grams into moles.

- Step 2. Then, we are going to use the equation proportion to calculate how many moles of each compound is consumed and formed.

- Step 3. Transform moles into grams of each compound.

Step 1:

mole = 3.59 x 10^2/ 65.38

mole = 5.49 moles of zinc

Step 2:

1 mole Zn --- 2 mole HCl

5.49 mole Zn --- x mole HCl

x = 10.98 moles

1 mole Zn --- 1 mole ZnCl2

5.49 mole Zn --- x mole ZnCl2

x = 5.49 moles of ZnCl2

1 mole Zn --- 1 mole H2

5.49 mole Zn --- x mole H2

x = 5.49 moles of H2

Step 3.

mass = mole x molar mass

molar mass of H2 = 2 g/mol

molar mass of ZnCl2 = 136.286 g/mol

molar mass of HCl = 36.458 g/mol

H2:

mass = 5.49 x 2

mass of H2 = 10.98 g

ZnCl2:

mass of ZnCl2 = 5.49 x 136.286 = 748 g

HCl

mass of HCl = 10.98 x 36.458 = 400 g