The reaction of removing CO2 using LiOH is the following:
2 LiOH + CO2 -----> Li2CO3 + H2O
By solving the amount of CO2 the LiOH can scrub:
(3.50 × 10^4 g LiOH) (1 mol LiOH/ 24 g LiOH) ( 1 mol CO2 / 2 mol LiOH) ( 44 g CO2 /1 mol CO2) = 32, 083.33 g CO2 it can scrub
Since number of astronaut = 32, 083.33 g / 9 (8.8 × 10^2) = 4 astronaut