3x 4y-5z=12 2x 5y-z=17 6x 2y-3z=17 x² y² z²=.....? please need answer

asked Apr 12, 2017 216k views

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3x 4y-5z=12
2x 5y-z=17
6x 2y-3z=17
x² y² z²=.....?
please need answer

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Is there a mistake in the given above? If there is, is this the correct given?
3x + 4y - 5z = 12
2x + 5y + z = 17
6x - 2y + 3z = 17
x^2 + y^2 + z^2?

Sam Rueby answered Apr 19, 2017

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