Answer: Angle FEH = 143.
Explanation:
Given : in the paper airplane shown ABCD is congruent to EFGH ... angle B= angle BCD= 90 and angle BAD = 143.
To find : angle FEH.
Solution : We have given quadrilateral ABCD is congruent to EFGH.
Shapes of quadrilateral ABCD and EFGH is trapezoid.
By congruent rule : side AB ≅ EF, BC≅FG, CD≅GH, DA≅HE and all corresponding angles are equal.
By given statement angle B = angle BCD = 90 and angle BAD = 143
We can see by congruent rule angle BAD ≅ angle FEH = 143.
Therefore, angle FEH = 143.