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Find the indicated limit, if it exists.

limit of f of x as x approaches negative 8 where f of x equals x plus 9 when x is less than negative 8 and f of x equals negative seven minus x when x is greater than or equal to negative 8

-8
1
17
The limit does not exist.

User GiDo
by
6.9k points

2 Answers

3 votes

Answer:

1

Explanation:

just took the test

User Redacted
by
7.2k points
3 votes
Find
{\displaystyle\lim_(x \rightarrow ~-8)f(x)}

where
{ f(x) = \begin{cases} & x+9,~~~~~~~~~~{\large x\ \textless \ -8} \\ & -7-x,~~~~~~{\large x\ge-8} \end{cases} }

So to find the left sided limit, you need to plug in -8, into x+9 and to find the right sided limit, you need to plug in -8, into -7-x.

If the two sides of the limit are no equivalent, then
{\displaystyle\lim_(x \rightarrow ~-8)f(x)~~DNE}

Since both sides are equal to 1, the limit is 1.
User Rickz
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7.3k points