Question

A youth hockey team has scored 6, 9, and 2 goals in three games in a hockeytournament. How many goals must they score in the fourth game for their average tobe greater than 5 goals per game?Solve the inequality

Answer 1

The youth hockey team already played 3 matches in which they scored 6, 9 and 2 goals.

Let

the score of the fourth goal = x

`\begin{gathered} (6+9+2+x)/(4)>5 \\ (17+x)/(4)>5 \\ \text{multiply both sides by 4} \\ ((17+x)/(4))4>5*4 \\ 17+x>20 \\ \text{subtract 17 from both sides} \\ 17-17+x>20-17 \\ x>3 \end{gathered}`

The number of goals must be greater than 3 for the average score to be greater than 5