Question

What is the fnet of the fbd in the middle

Answer 1

-200 N

Step-by-step explanation

Step 1

we can see that on the object are acting vertical forces, if we assume the y-positive axis as positive ( upwards) then we have

`\begin{gathered} \sum ^(\square)_{\text{xorce-in y}}=600N-800N \\ \sum ^(\square)_{\text{xorce-in y}}=-200\text{ N} \end{gathered}`

therefore, the answer is -200