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a circle has its center at (−2, 5) and a radius of 4 units. what is the equation of the circle? (1 point) (x 2)2 (y − 5)2 = 16 (x 2)2 (y 5)2 = 16 (x 2)2 (y − 5)2 = 4 (x − 2)2 (y 5)2 = 4

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4 votes
( x + 2 )^2 + ( y - 5 )^2 = 16

the answer is the first one
User CoperNick
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5 votes

Answer:


(x+2)^2+(y-5)^2=16

Explanation:

We have been given that a circle has its center at (−2, 5) and a radius of 4 units. We are asked to write the equation of the circle.

We know that standard equation of circle is in form
(x-h)^2+(y-k)^2=r^2, where, (h,k) represents vertex of circle and r represents radius of circle.

Upon substituting coordinates of vertex
(-2,5) and
r=4 in above equation, we will get:


(x-(-2))^2+(y-5)^2=4^2


(x+2)^2+(y-5)^2=16

Therefore, the equation of our given circle would be
(x+2)^2+(y-5)^2=16.

User Kurtbaby
by
8.5k points

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