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1 vote
Match the range of the function f(x) = x2 + 2x _ 1 to its domain.

Tiles
2
-2
3
-3
Pairs
2
arrowBoth
-14
arrowBoth
7
arrowBoth
-1
arrowBoth

User Jiovanny
by
8.7k points

2 Answers

2 votes
I hope this helps you




f(2)=2^2+2.2-1=4+4-1=7



f (-2)=(-2)^2+2. (-2)-1 =4-4-1= -1



f (3)=3^2+2.3-1=9+6-1=14



f (-3)=(-3)^2+2. (-3)-1=9-6-1=2
User Calrion
by
8.1k points
4 votes

Answer:

The pair of coordinates of domain and range are (2,7),(-2,1),(3,14) and (-3,2).

Explanation:

Domain is the set of inputs of x values and range is the set of outputs or f(x) values.

The given function is


f(x)=x^2+2x-1

Substitute x=2 in the given function,


f(2)=(2)^2+2(2)-1=7

The value of the function is 7 at x=2.

Substitute x=-2 in the given function,


f(-2)=(-2)^2+2(-2)-1=-1

The value of the function is -1 at x=-2.

Substitute x=3 in the given function,


f(3)=(3)^2+2(3)-1=14

The value of the function is 14 at x=3.

Substitute x=-3 in the given function,


f(-3)=(-3)^2+2(-3)-1=2

The value of the function is 2 at x=-3.

Therefore the pair of coordinates of domain and range are (2,7),(-2,1),(3,14) and (-3,2).

User Eigenvalue
by
7.5k points
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