Question

The figure below shows triangle ABC on the coordinate plane. у 10 9 8 7 6 B 5 3 2 с -10 -9 8 7 6 5 3 2 1 2 3 4 5 6 7 B = 9 10 A -10 Write the coordinates of the vertices of a triangle A'B'C'that results from a translation of triangle ABC two units to the right and four units down. Al BU cd

Answer 1

We are given a triangle and we are asked to translate its vertices two units to the right and four units down. To do that we will use the following rule for the transformation:

`(x^(\prime),y^(\prime))\rightarrow(x+2,y-4)`

The coordinates of vertex A is:

`A=(2,-2)`

Applying the rule we get:

`\begin{gathered} A^(\prime)(2,-2)=(2+2,-2,-4) \\ A^(\prime)(2,-2)=(4,-6) \end{gathered}`

The coordinates of point B are:

`B=(-2,5)`

Applying the rule we get:

`\begin{gathered} B^(\prime)(-2,5)=(-2+2,5-4) \\ B^(\prime)(-2,5)=(0,1) \end{gathered}`

The coordinates of point C:

`C=(-4,2)`

Applying the rule:

`\begin{gathered} C^(\prime)(-4,2)=(-4+2,2-4) \\ C^(\prime)(-4,2)=(-2,-2) \end{gathered}`