Question

2 Solve the equation tan²B = 1 given that 0

Answer 1

β = π/4, 3π/4

Step-by-step explanation:

If tan²β = 1, we can solve the equation finding the square root, so

`\begin{gathered} \tan \beta=\pm\sqrt[]{1} \\ \tan \beta=1\text{ or tan}\beta\text{ = -1} \end{gathered}`

Now, we know that tanβ = 1 if β = π/4 y tanβ = -1 if β = 3π/4.

Therefore, the answers are:

β = π/4, 3π/4