Question

This figure shows the nose cone of a rocket used for launching satellites. The nose cone houses the satellite until the satellite is placed in orbit. What is the volume of the nose cone?

Answer 1

The rule of the volume of the cone is

`V=(1)/(3)\pi r^2h`

r is the radius of the base

h is the height of the cone

From the picture, we can see

The diameter of the base is 6 feet and the height is 15 feet

Since the radius is half the diameter, then

`\begin{gathered} r=(1)/(2)d \\ r=(1)/(2)(6) \\ r=3 \end{gathered}`

Substitute r by 3 and h by 15 to find the volume

`\begin{gathered} V=(1)/(3)(\pi)(3)^2(15) \\ V=45\pi\text{ f}eet^3 \end{gathered}`

The volume of the cone is 45pi feet^3

The answer is A