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Solve each system by substitution x+12y=68 x=8y-12
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5 votes
Solve each system by substitution x+12y=68

x=8y-12

User Yilmazhuseyin
by
7.7k points

1 Answer

7 votes
substitute x=8y-12 into first equation
8y-12+12y=68
20y=68+12
20y=80
y=80/20
y=4

substitute y=4 in 2nd equ
x=8(4)-12
x=32-12
x=20
User Roman Shamritskiy
by
8.7k points
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