Question

What load would a beam 5 in. Wide, 4 in. deep and 17ft Long of the same material support? Round off your answer to the nearest pound.

Answer 1

`\begin{gathered} \text{Load}=K\cdot(wd^2)/(l) \\ w=\text{width} \\ d=\text{depth} \\ l=length \\ \text{For} \\ \text{Load}=1090lb \\ w=6in \\ d=9in \\ l=12ft \\ \text{The constant K could be found} \\ \text{Solving K} \\ \text{Load}=K\cdot(wd^2)/(l) \\ \text{Load}\cdot l=Kwd^2 \\ K=\frac{\text{Load}\cdot l}{wd^2} \\ U\sin g\text{ the values} \\ K=((1090)\cdot(12))/((6)(9)^2) \\ K=26.91 \\ \text{The value of K is 26.91} \\ \text{Now, the load can be calculated} \\ w=5in \\ d=4in\text{ } \\ l=17ft \\ \text{Load}=K\cdot(wd^2)/(l) \\ \text{Load}=(\text{26.91})\cdot((5)(4)^2)/((17)) \\ \text{Load}=126.63 \\ \text{The new load is }126.63\text{ lb} \end{gathered}`