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The half-life of radon-222 is 3.8 days. How much of a 100 kg sample is left after 15.2 days?

User Martin Epsz
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1 Answer

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12 votes

Let t_0 be the half life of a radioactive element. Radioactive decay is modelled as a negative exponential function. Let A_0 be the initial amount of the sample. The amount A of radioactive element in that sample after t days is given by the formula:


A=A_0e^(-t/t_0)

Substitute A_0=100kg, t=15.2 d and t_0=3.8d:


\begin{gathered} A=(100\operatorname{kg})* e^(-15.2/3.8) \\ =(100\operatorname{kg})* e^(-4) \\ =(100\operatorname{kg})*0.0183156\ldots \\ =1.831563\ldots kg \end{gathered}

Therefore, the amount of radon-222 that is left from a 100kg sample after 15.2 days is, approximately:


1.83\operatorname{kg}

User Dieter Gribnitz
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