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Determine the angle of rotation of the conic section given by: x2 + xy+ y2 = 10 (round your answer to the nearest tenth of a degree).

User Eduardo Almeida
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The general form of a conic section is:

Ax²+Bxy+Cy²+Dx+Ey+F=0

If B does not equal 0, then the conic section has been rotated. In this problem, we have

x² + xy + y² = 10

Thus: B = 1 (coefficient of xy), A = 1 (coefficient of x²), and C = 1 (coefficient of y²).

And the angle of rotation, θ, can be found using the formula:

cot (2θ) = (A - C)/B

Notice that "cot (2θ)" represents the reverse of the tangent function, that is, 1/tan(2θ).

Now, let's use A = B = C = 1 in that formula:

cot (2θ) = (1 - 1)/1 = 0/1 = 0

Since we obtained zero, that means the tangent of 2θ is infinity. And the angle for which this is true is 90º ( π/2).

Then,

2θ = 90º

θ = 90º/2

θ = 45º

Determine the angle of rotation of the conic section given by: x2 + xy+ y2 = 10 (round-example-1
User Cmsjr
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