Question

Iron(III) oxide reacts with carbon to give iron and carbon monoxide:Fe2O3(s)+3C(s)→2Fe(s)+3CO(g)How many grams of CO are produced when 33.0 g of C reacts?

Answer 1

We will firstly convert the mass into moles to dfeine the relationship using mole ratio.

`Fe_2O_(3(s))+3C_((s))\rightarrow2Fe_((s))+3CO_((g))`
`\begin{gathered} _nC_((s))=\frac{mass}{molar\text{ }mass} \\ \\ _nC_((s))=\frac{33.0\text{ }g}{12\text{ }gmol^(-1)} \\ _nC_((s))=2.75\text{ }mol \end{gathered}`

The mole ratio between C and CO is 3:3 or 1:1. Therefore 2.75 mol of carbon would produce 2.75 mol of carbon monoxide. Using this relationship we will convert moles to mass.

`\begin{gathered} mass\text{ }CO=moles* molar\text{ }mass \\ mass\text{ }CO=2.75\text{ }moles*28\text{ }gmol^(-1) \\ mass\text{ }CO=77g \end{gathered}`

Answer: 77.0g of CO are produced when 33.0g of C reacts.