Question

Denver's elevation is 1 like (5,280 feet) The elevation of loveland pass, 70 miles west of denver, is 11,990 feet. What is the average slope of the land from deny to loveland pass

Answer 1

`\text{slope}=-95.85`

Step-by-step explanation

when you know 2 poitns of a line, you can find the slope by appling

`\begin{gathered} \text{slope}=\frac{change\text{ in y }}{\text{change in x}}=(y_2-y_1)/(x_2-x_1) \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}`

then

let

P1= denver=(0,5280)

P2=loveland=(-70,11990)

replace

`\begin{gathered} \text{slope}=(11990-5280)/(-70-0) \\ \text{slope}=(6710)/(-70) \\ \text{slope}=-95.85 \end{gathered}`

I hope this helps you