125k views
5 votes
How many moles of isooctane must be burned to produce 100 kJ of heat under standard state conditions? Show all of your work.

2 Answers

2 votes

Answer:


mol_(isooct)= 0.0183 mol

Step-by-step explanation:

Hi, to calculate the moles needed for that energy requirement, first you need to understand the combustion reaction:


C_8H_1_8 + 25/2 O_2 \longrightarrow 8 CO_2 + 9 H_2O

Now, you need the heat of reaction. You can either search for it in tables or calculate it from the heats of formation.

For isooctane:
\Delta H_(comb)=-5450 kJ/mol

The last step is just a simple calculation:


mol_(isooct)=(100kJ)/(5450kJ/mol)


mol_(isooct)= 0.0183 mol

User Andre Elrico
by
8.8k points
2 votes

According to Prosen and Rossini, 1945, the standard heat of combustion of isooctane is -5461.3 kJ/mol. The negative sign is just to depict that there was a release of energy. Thus, to produce 100 kJ energy,

100 kJ ÷ 5461.3 kJ/mol isooctane = 0.0183 moles isooctane.

0.0183 moles of isooctane must be burned.

I hope I was able to answer your question J

User JJSmith
by
8.5k points