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Zeros of fx³ - 5x² + 36x - 180 Zeros of the function = ?

User OganM
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1 Answer

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14 votes

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

x³ - 5x² + 36x - 180

Zeros of the function = ?

Step 02:

Zeros of the function

x³ - 5x² + 36x - 180 = 0

(x - 5) (x² + 36) = 0

x - 5 = 0

x² + 36 = 0

x - 5 = 0

x = 5

x² + 36 = 0

x = √-36

x = 6i

x = -6i

The answer is:

x1 = 5

x2 = 6i

x3 = -6i

User Matt Ollis
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