Question

Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO.

Fe2O3 + 3CO --> 2Fe + 3CO2

In the process, 213 g of Fe2O3 are reacted with 140 of CO.
(a) calculate mass of Fe formed
(b) how many moles of the excess reagent is left at the end of the reaction?

Pls show me how to calculate this using dimensional analysis :(

Answer 1

Fe2O3 + 3CO --> 2Fe + 3CO2

m(Fe2O3)=213 g
m(CO)=140 g
_______________

n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?

n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol

n(CO)= m(CO) / M(CO) n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol