Question

X^2 - 10x- 3 =0 to the nearest tenth

Answer 1

Given:

`x^2-10x-3=0`

Find the solution.

Sol:

Use quadratic formula then,

`\begin{gathered} ax^2+bx+c=0 \\ \\ x=(-b\pm√(b^2-4ac))/(2a) \end{gathered}`

Apply the formula is:

`\begin{gathered} x^2-10x-3=0 \\ \\ x=(-(-10)\pm√((-10)^2-4(1)(-3)))/(2(1)) \\ \\ x=(10\pm√(100+12))/(2) \\ \\ x=(10\pm√(112))/(2) \end{gathered}`

So the value of x is:

`\begin{gathered} x=(10\pm√(112))/(2) \\ \\ x=(10\pm√(28*4))/(2) \\ \\ x=(2(5\pm√(28)))/(2) \\ \\ x=5\pm√(28) \\ \\ x=5\pm5.29 \\ \\ x=0.29,x=10.29 \end{gathered}`

So the value of "x" is 0.3 and 10.3