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11 votes
If 12,027.5 J of heat are absorbed by 760.6 g of water, what will be the change in temperature

User Matt Eckert
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1 Answer

13 votes
13 votes

Answer

ΔT = 3.78x10^-3 °C

Step-by-step explanation

Given:

Energy (Q) = 12.0275 J

Mass of water = 760.6 g

We know the specific heat capacity of water = 4.182 J/g °C

Required: The change in temperature

Solution

Q = m x Cp x ΔT

ΔT = Q/m x Cp

ΔT = 12.0275 J/(760.0 g x 4.182 J/g °C)

ΔT = 3.78x10^-3 °C (or 0.00378 °C)

User Tarun Tyagi
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