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find the probability of getting 4 consecutive aces when four cards are drawn without replacement from a standard deck of 52 playing cards

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there are 4 aces in a deck of 52 cards

probability of 1st card being an ace = 4/52
without replacement
probability of 2nd card being an ace = 3/51
without replacement
probability of 3rd card being an ace = 2/50
without replacement
probability of 4th card being an ace = 1/49

probability of all 4 cards being aces : 4/52 * 3/51 * 2/50 * 1/49 =
24/6,497,400 reduces 1/270,725
User Evgeniya Manolova
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