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5 votes
5 votes
At the city Museum, child admission in $5.30 and adult admission is $9.30. On Saturday, twice as many adult tickets as child tickets were sold, for a total sale of $860.40. How many child tickets were sold that day?

User Daniel De Freitas
by
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1 Answer

21 votes
21 votes

Assume that the number of child tickets on Saturday is x

Since the number of adult tickets is twice the number of the child tickets, then

The number of adult tickets is 2x

Since the child admission is $5.30

Since the adult admission is $9.30

Since the total amount of admission is $860.40, then

Multiply x by 5.30 and 2x by 9.30, then add the products and equate the sum by 860.40


5.30(x)+9.30(2x)=860.40

Simplify the left side


\begin{gathered} 5.30x+18.60x=860.40 \\ 23.90x=860.40 \end{gathered}

Divide both sides by 23.90


\begin{gathered} (23.90x)/(23.90)=(860.40)/(23.90) \\ x=36 \end{gathered}

The number of child tickets sold on Saturday was 36

User Saarthak
by
2.5k points
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