Question

P(Z < -1.02) =0.11510.15390.84610.8849

Answer 1

The probability of a z-value less than -1.02 is similar to getting the area to the left of z = -1.02 in a normal curve.

Using the standard normal distribution table, the area to the left of z = -1.02 is 0.1539. Therefore, P(Z < -1.02) = 0.1539.